Limits

By:Mohammad-Ali Bandzar | Nov 1 2019

Understanding the logic behind limits

one sided limits from the left

A limit from the left is written in the general form: loading... notice the "negative" exponent on the value we are aproaching, that means that we only want to aproach a from the left and that we will only test x values that are less than but very close to a.

a very popular example of this is loading
but our two sided limit does not exist, i will explain why below

one sided limits from the right

A limit from the left is written in the general form: loading... notice the "positive" exponent on the value we are aproaching, that means that we only want to aproach a from the right and that we will only test x values that are greater than but very close to a.

Continuing our example from above our right sided limit would be loading...

two sided/normal limits

we can only say that the two sided limit exists if both one sided limits exist and are equal to each other, that is:loading....

continuing our example from before, we can say that loading... does not exist because loading... which can be visualized better with a graph

Limit solving stratagies

Many different aproaches exist for solving limits, when i was in highschool i used a scientific calculator to plug in really close numbers from both sides to determine the limit, but that isnt a "valid" aproach according to most teachers, but is still a completely valid way of validating your solutions

Direct substition

Sometimes you can directly plug your number into the equation and get a result, beware that if this value is on the very edge of your domain there maybe no solution to your limit.
if we were to try and solve through direct substitition we would get zero, but some may argue that the limit does not exist as we cannot solve for a limit from the left as the function is not define for any number to the left of(less than) zero. you should definately clairify with your instructor about this

Anouther common issue with this method is when you plug into a function that looks like the following:
the issue here is that the limit does not exist as x aproaches zero but f(0)=2 so if you were to just plug in without verifying your solution you can get limits that dont exist or are incorrect.
OR.
Here, the limit does exist, but just pluging in would give you the wrong answer.

Factoring

This is the most common method it involves essentially removing the hole from the equation then directly substituting the value, a simple example of this is loading... if we factor the binomial we get loading... we can then “cancel out” loading... from both our numerator and denominator to get loading... from there we can directly substitute to get the solution to our limit which is -6

Multiplying by a conjugate

Sometimes you will get a question such as loading... and and you want to solve for the limit as x approaches 9 so you can multiple by the cojgare divided by itself( which is essentially multiplying by one, to get loading...) which simplifies to we can then “cross out” the common factor to get loading... we can then substitute in the 9 to get loading... as our limit.

Limits approaching infinity:

These limits are only tested from one side and can only have one of 3 possible values,

• a fixed number for a horizontal line or asymptote.
• Positive infinity for something going upward
• negative infinity for something going downward.
I would recommend reading my tutorial on horizontal asymptotes to better understand how to solve these

Example 1:

loading... this one is fairly easy because the bigger x we plug in we can see that x squared goes bigger, so we can say that loading...

Example 2:

Example 3:

loading... this one does not exist because the two one sided limits are not equal. from the left its negative one, from the right its positive one.

Example 4:

loading... this limit does not exist because it is a vertical asymptote. the missing value is impossible to factor out and direct substitution gives us loading... which is not the indeterminate form and will always be a vertical asymptote.

Example 5:

loading... this limit does not exist because it is a vertical asymptote. the missing value is impossible to factor out and direct substitution gives us loading... which is not the indeterminate form and will always be a vertical asymptote.

Example 6:

loading... as x is going toward negative infinity we can restrict our domain to x<0 and rewrite this as loading... from here it should be fairly clear to you that one divided by a constantly increasing number will be zero. another way to look at it would be loading... which isnt technically mathamatically correct but should make it more clear to you about why our solution is zero.

Example 7:

loading... This one starts with us pulling the common factor out of our numerator: loading... From there we can factor the numberator: loading... from there we can cross out the common factor loading... to get our final solution: loading...=-12

Fun use case

using your new found knowledge of limits you can now tell your friends you can solve loading...(sort of) by defining a function loading... we can then take the limit of that as x aproaches zero loading... which is one.

Pro tips:

• limits to infinity can’t be evaluated from both sides
• always remember to evaluate limits from both sides where possible
• limits don’t always have to be indeterminate values of the function
• limits are most commonly used to identify and solve for holes in a function
• limits can only exist if they take the indeterminate form(a hole, loading...) or a solution when directly plugged into
• remember to test your solution from both sidesif you are directly substituting in
• Use a graphing calculator/desmos.com to verify your solutions
• limits of vertical asymptotes are technically undefined/D.N.E(does not exist) but some people will still write them as loading...
• THANKS FOR READING